154340
  -OEChem-02060822392D

 11 12  0     1  0  0  0  0  0999 V2000
    1.1229   -1.8853    0.0000 O   0  0  0  0  0  0  0  0  0  0  0  0
   -1.1974    0.0910    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
   -0.0132    0.6185    0.0000 C   0  0  3  0  0  0  0  0  0  0  0  0
   -0.2216    0.2563    0.0000 C   0  0  3  0  0  0  0  0  0  0  0  0
    0.7988    0.1538    0.0000 C   0  0  3  0  0  0  0  0  0  0  0  0
   -0.1422    1.4107    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    1.1279   -1.0634    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    0.5937   -0.1902    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
   -1.9316    0.5706    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
   -1.6587   -0.7409    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    1.5215    0.7773    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
  1  7  2  0  0  0  0
  2  3  1  0  0  0  0
  2  4  1  0  0  0  0
  2  9  1  0  0  0  0
  2 10  1  0  0  0  0
  3  5  1  0  0  0  0
  3  6  1  0  0  0  0
  4  6  1  0  0  0  0
  4  8  1  0  0  0  0
  5  7  1  0  0  0  0
  5 11  1  0  0  0  0
  7  8  1  0  0  0  0
M  END
> <PUBCHEM_COMPOUND_ID_TYPE>
0

> <PUBCHEM_TOTAL_CHARGE>
0

> <PUBCHEM_SUBSTANCE_ID>
154340

> <PUBCHEM_SUBSTANCE_VERSION>
3

> <PUBCHEM_EXT_DATASOURCE_NAME>
ChemIDplus

> <PUBCHEM_EXT_DATASOURCE_REGID>
000547604

> <PUBCHEM_SUBSTANCE_SYNONYM>
(1)-(1alpha,2alpha,5alpha)-2,6,6-Trimethylbicyclo(3.1.1)heptan-3-one
(1alpha,2alpha,5alpha)-2,6,6-Trimethylbicyclo(3.1.1)heptan-3-one
2,6,6-TRIMETHYLBICYCLO(3.1.1)HEPTAN-3-ONE
30517-87-4
547-60-4
Bicyclo(3.1.1)heptan-3-one, 2,6,6-trimethyl-, (1R,2S,5S)-rel-
Bicyclo(3.1.1)heptan-3-one, 2,6,6-trimethyl-, (1alpha,2alpha,5alpha)-
EINECS 208-926-9
EINECS 250-226-0
Pinocamphone

> <PUBCHEM_GENERIC_REGISTRY_NAME>
30517-87-4
547-60-4

> <PUBCHEM_XREF_EXT_ID>
000547604

> <PUBCHEM_EXT_DATASOURCE_URL>
http://chem.sis.nlm.nih.gov/chemidplus/

> <PUBCHEM_EXT_SUBSTANCE_URL>
http://chem.sis.nlm.nih.gov/chemidplus/direct.jsp?result=advanced&regno=000547604

> <PUBCHEM_CID_ASSOCIATIONS>
11038  1

$$$$