196785 -OEChem-02060822412D 25 26 0 0 0 0 0 0 0999 V2000 5.4276 3.0241 0.0000 Br 0 5 0 0 0 0 0 0 0 0 0 0 -3.2034 -0.5931 0.0000 S 0 0 0 0 0 0 0 0 0 0 0 0 0.3276 2.8552 0.0000 O 0 0 0 0 0 0 0 0 0 0 0 0 -0.8483 0.7862 0.0000 N 0 0 0 0 0 0 0 0 0 0 0 0 2.6759 -1.2138 0.0000 N 0 3 0 0 0 0 0 0 0 0 0 0 -2.0517 1.4862 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 -0.8517 -0.5552 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 -3.2241 0.7931 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 -2.0241 -1.2310 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 0.3276 1.4724 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 -2.0655 2.8690 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 0.3276 -1.2448 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 -4.4103 1.4724 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 -2.0345 -2.6138 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 1.5034 0.8207 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 -3.2483 3.5448 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 0.3276 -2.6276 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 -4.4138 2.8552 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 -0.8862 -3.3138 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 1.5138 -0.5655 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 2.0138 -2.4138 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 3.3655 -0.0448 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 3.8517 -1.8931 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 2.6759 -3.5931 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 4.9138 -0.0793 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 2 8 1 0 0 0 0 2 9 1 0 0 0 0 3 10 2 0 0 0 0 4 6 1 0 0 0 0 4 7 1 0 0 0 0 4 10 1 0 0 0 0 5 20 1 0 0 0 0 5 21 1 0 0 0 0 5 22 1 0 0 0 0 5 23 1 0 0 0 0 6 8 1 0 0 0 0 6 11 2 0 0 0 0 7 9 2 0 0 0 0 7 12 1 0 0 0 0 8 13 2 0 0 0 0 9 14 1 0 0 0 0 10 15 1 0 0 0 0 11 16 1 0 0 0 0 12 17 2 0 0 0 0 13 18 1 0 0 0 0 14 19 2 0 0 0 0 15 20 1 0 0 0 0 16 18 2 0 0 0 0 17 19 1 0 0 0 0 21 24 1 0 0 0 0 22 25 1 0 0 0 0 M CHG 2 1 -1 5 1 M END > 0 > 0 > 196785 > 3 > ChemIDplus > 111327403 > 111327-40-3 AMMONIUM, DIETHYLMETHYL(2-(10-PHENOTHIAZINYLCARBONYL)ETHYL)-, BROMIDE Diethylmethyl(2-(10-phenothiazinylcarbonyl)ethyl)ammonium bromide > 111327-40-3 > 111327403 > http://chem.sis.nlm.nih.gov/chemidplus/ > http://chem.sis.nlm.nih.gov/chemidplus/direct.jsp?result=advanced®no=111327403 > 60488 1 260 2 60489 2 $$$$