771370
  -OEChem-02060822482D

 14 15  0     0  0  0  0  0  0999 V2000
   15.1623   -0.6881    0.0000 N   0  0  0  0  0  0  0  0  0  0  0  0
   16.5156    0.8150    0.0000 N   0  0  0  0  0  0  0  0  0  0  0  0
   15.2929    0.5551    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
   16.3042   -1.1965    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
   14.0798   -1.3131    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
   10.8322   -0.6881    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
   17.1406   -0.2675    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
   12.9972   -0.6881    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
   11.9147   -1.3131    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
   10.8322    0.5619    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    9.7496   -1.3131    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    9.7496    1.1869    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    8.6671   -0.6881    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    8.6671    0.5619    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
  1  3  1  0  0  0  0
  1  4  1  0  0  0  0
  1  5  1  0  0  0  0
  2  3  2  0  0  0  0
  2  7  1  0  0  0  0
  4  7  2  0  0  0  0
  5  8  1  0  0  0  0
  6  9  1  0  0  0  0
  6 10  2  0  0  0  0
  6 11  1  0  0  0  0
  8  9  2  0  0  0  0
 10 12  1  0  0  0  0
 11 13  2  0  0  0  0
 12 14  2  0  0  0  0
 13 14  1  0  0  0  0
M  END
> <PUBCHEM_COMPOUND_ID_TYPE>
0

> <PUBCHEM_TOTAL_CHARGE>
0

> <PUBCHEM_SUBSTANCE_ID>
771370

> <PUBCHEM_SUBSTANCE_VERSION>
3

> <PUBCHEM_EXT_DATASOURCE_NAME>
ChemIDplus

> <PUBCHEM_EXT_DATASOURCE_REGID>
056643937

> <PUBCHEM_SUBSTANCE_SYNONYM>
1-(3-Phenyl-2-propenyl)-1H-imidazole
1H-Imidazole, 1-(3-phenyl-2-propenyl)-
56643-93-7
SQ 80,338
SQ 80338

> <PUBCHEM_GENERIC_REGISTRY_NAME>
56643-93-7

> <PUBCHEM_XREF_EXT_ID>
056643937

> <PUBCHEM_EXT_DATASOURCE_URL>
http://chem.sis.nlm.nih.gov/chemidplus/

> <PUBCHEM_EXT_SUBSTANCE_URL>
http://chem.sis.nlm.nih.gov/chemidplus/direct.jsp?result=advanced&regno=056643937

> <PUBCHEM_CID_ASSOCIATIONS>
6443808  1

$$$$