787420
  -OEChem-02060822482D

 13 13  0     1  0  0  0  0  0999 V2000
    1.0404   -1.4738    0.0000 S   0  0  0  0  0  0  0  0  0  0  0  0
    1.0404    0.6913    0.0000 S   0  0  0  0  0  0  0  0  0  0  0  0
    2.9154   -0.3913    0.0000 N   0  0  0  0  0  0  0  0  0  0  0  0
    5.4154   -0.3913    0.0000 N   0  0  3  0  0  0  0  0  0  0  0  0
    3.5404    0.6913    0.0000 C   0  0  3  0  0  0  0  0  0  0  0  0
    4.7904    0.6913    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    1.6654   -0.3913    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    3.5404   -1.4738    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    4.7904   -1.4738    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    6.6654   -0.3913    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    2.9154    1.7738    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    7.2904   -1.4738    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    8.5404   -1.4738    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
  1  7  2  0  0  0  0
  2  7  1  0  0  0  0
  3  5  1  0  0  0  0
  3  7  1  0  0  0  0
  3  8  1  0  0  0  0
  4  6  1  0  0  0  0
  4  9  1  0  0  0  0
  4 10  1  0  0  0  0
  5  6  1  0  0  0  0
  5 11  1  0  0  0  0
  8  9  1  0  0  0  0
 10 12  1  0  0  0  0
 12 13  2  0  0  0  0
M  END
> <PUBCHEM_COMPOUND_ID_TYPE>
0

> <PUBCHEM_TOTAL_CHARGE>
0

> <PUBCHEM_SUBSTANCE_ID>
787420

> <PUBCHEM_SUBSTANCE_VERSION>
3

> <PUBCHEM_EXT_DATASOURCE_NAME>
ChemIDplus

> <PUBCHEM_EXT_DATASOURCE_REGID>
026864915

> <PUBCHEM_SUBSTANCE_SYNONYM>
1-Piperazinecarbodithioic acid, 4-allyl-2-methyl-
2-Methyl-4-(2-propenyl)-1-piperazinecarbodithioic acid
26864-91-5
4-Allyl-2-methyl-1-piperazinecarbodithioic acid
5-23-03-00273 (Beilstein Handbook Reference)
BRN 0513818

> <PUBCHEM_GENERIC_REGISTRY_NAME>
26864-91-5

> <PUBCHEM_XREF_EXT_ID>
026864915

> <PUBCHEM_EXT_DATASOURCE_URL>
http://chem.sis.nlm.nih.gov/chemidplus/

> <PUBCHEM_EXT_SUBSTANCE_URL>
http://chem.sis.nlm.nih.gov/chemidplus/direct.jsp?result=advanced&regno=026864915

> <PUBCHEM_CID_ASSOCIATIONS>
213678  1

$$$$