3865055 -OEChem-02060822592D 24 27 0 1 0 0 0 0 0999 V2000 5.4967 3.0484 0.0000 Cl 0 0 0 0 0 0 0 0 0 0 0 0 4.8455 -3.1067 0.0000 O 0 0 0 0 0 0 0 0 0 0 0 0 -0.9966 -0.7931 0.0000 O 0 0 0 0 0 0 0 0 0 0 0 0 -0.9966 -2.9582 0.0000 O 0 0 0 0 0 0 0 0 0 0 0 0 7.0417 -2.0784 0.0000 N 0 0 0 0 0 0 0 0 0 0 0 0 8.8199 -1.1366 0.0000 N 0 0 0 0 0 0 0 0 0 0 0 0 4.6284 -1.8757 0.0000 C 0 0 3 0 0 0 0 0 0 0 0 0 5.8031 -2.3032 0.0000 C 0 0 3 0 0 0 0 0 0 0 0 0 3.3784 -1.8757 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 4.8455 -0.6447 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 2.7534 -2.9582 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 2.7534 -0.7931 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 6.0201 -0.2171 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 3.8879 0.1588 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 7.5820 -0.9627 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 7.9256 -2.9622 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 1.5034 -2.9582 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 1.5034 -0.7931 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 0.8784 -1.8757 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 6.2372 1.0139 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 4.1050 1.3898 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 9.0171 -2.3320 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 5.2796 1.8173 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 -0.3716 -1.8757 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 1 23 1 0 0 0 0 2 7 1 0 0 0 0 2 8 1 0 0 0 0 3 24 2 0 0 0 0 4 24 1 0 0 0 0 5 8 1 0 0 0 0 5 15 1 0 0 0 0 5 16 1 0 0 0 0 6 15 2 0 0 0 0 6 22 1 0 0 0 0 7 8 1 0 0 0 0 7 9 1 0 0 0 0 7 10 1 0 0 0 0 9 11 2 0 0 0 0 9 12 1 0 0 0 0 10 13 2 0 0 0 0 10 14 1 0 0 0 0 11 17 1 0 0 0 0 12 18 2 0 0 0 0 13 20 1 0 0 0 0 14 21 2 0 0 0 0 16 22 2 0 0 0 0 17 19 2 0 0 0 0 18 19 1 0 0 0 0 19 24 1 0 0 0 0 20 23 2 0 0 0 0 21 23 1 0 0 0 0 M END > 0 > 0 > 3865055 > 2 > ChemIDplus > 079478709 > 1-(1,2-Epoxy-2-(4-chlorophenyl)-2-(4-carboxyphenyl)ethyl)imidazole 4-(2-(4-Chlorophenyl)-3-(1H-imidazol-1-yl)oxiranyl)benzoic acid 79478-70-9 Benzoic acid, 4-(2-(4-chlorophenyl)-3-(1H-imidazol-1-yl)oxiranyl)- > 79478-70-9 > 079478709 > http://chem.sis.nlm.nih.gov/chemidplus/ > http://chem.sis.nlm.nih.gov/chemidplus/direct.jsp?result=advanced®no=079478709 > 3061573 1 $$$$