172275
  -OEChem-02060822402D

 13 10  0     0  0  0  0  0  0999 V2000
   -0.4379    2.1483    0.0000 Ca  0  2  0  0  0  0  0  0  0  0  0  0
   -1.3724   -0.6276    0.0000 S   0  5  0  0  0  0  0  0  0  0  0  0
    1.4552   -0.8069    0.0000 S   0  5  0  0  0  0  0  0  0  0  0  0
   -2.9448    2.0931    0.0000 S   0  0  0  0  0  0  0  0  0  0  0  0
    2.9759    2.3483    0.0000 S   0  0  0  0  0  0  0  0  0  0  0  0
   -4.5138   -0.6276    0.0000 N   0  0  0  0  0  0  0  0  0  0  0  0
    4.5931   -0.6517    0.0000 N   0  0  0  0  0  0  0  0  0  0  0  0
   -2.9448    0.2828    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    2.9759    0.2690    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
   -6.0759    0.2828    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
   -4.5138   -2.4759    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    6.2000    0.2828    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    4.6000   -2.5138    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
  2  8  1  0  0  0  0
  3  9  1  0  0  0  0
  4  8  2  0  0  0  0
  5  9  2  0  0  0  0
  6  8  1  0  0  0  0
  6 10  1  0  0  0  0
  6 11  1  0  0  0  0
  7  9  1  0  0  0  0
  7 12  1  0  0  0  0
  7 13  1  0  0  0  0
M  CHG  3   1   2   2  -1   3  -1
M  END
> <PUBCHEM_COMPOUND_ID_TYPE>
0

> <PUBCHEM_TOTAL_CHARGE>
0

> <PUBCHEM_SUBSTANCE_ID>
172275

> <PUBCHEM_SUBSTANCE_VERSION>
3

> <PUBCHEM_EXT_DATASOURCE_NAME>
ChemIDplus

> <PUBCHEM_EXT_DATASOURCE_REGID>
020279690

> <PUBCHEM_SUBSTANCE_SYNONYM>
20279-69-0
81189-18-6
CARBAMIC ACID, DIMETHYLDITHIO-, CALCIUM SALT
Calcium dimethylcarbamodithioate
Calcium dimethyldithiocarbamate
Carbamodithioic acid, dimethyl-, calcium salt
Dimethyldithiocarbamic acid calcium salt
KSDK

> <PUBCHEM_GENERIC_REGISTRY_NAME>
20279-69-0
81189-18-6

> <PUBCHEM_XREF_EXT_ID>
020279690

> <PUBCHEM_EXT_DATASOURCE_URL>
http://chem.sis.nlm.nih.gov/chemidplus/

> <PUBCHEM_EXT_SUBSTANCE_URL>
http://chem.sis.nlm.nih.gov/chemidplus/direct.jsp?result=advanced&regno=020279690

> <PUBCHEM_CID_ASSOCIATIONS>
30090  1
6599  2
5460341  2

$$$$