208675
  -OEChem-02060822402D

 13 14  0     0  0  0  0  0  0999 V2000
    0.0000    1.7328    0.0000 O   0  0  0  0  0  0  0  0  0  0  0  0
    2.0000    1.7328    0.0000 N   0  0  0  0  0  0  0  0  0  0  0  0
    1.9991   -0.0028    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    2.4983   -0.8633    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    2.5000    0.8667    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    0.9991   -0.0018    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    3.5000    0.8657    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    3.4983   -0.8643    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    1.9974   -1.7328    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    3.9991   -0.0047    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    0.4983   -0.8613    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    0.9974   -1.7318    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    1.0000    1.7328    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
  1 13  2  0  0  0  0
  2  5  1  0  0  0  0
  2 13  2  0  0  0  0
  3  4  1  0  0  0  0
  3  5  2  0  0  0  0
  3  6  1  0  0  0  0
  4  8  2  0  0  0  0
  4  9  1  0  0  0  0
  5  7  1  0  0  0  0
  6 11  2  0  0  0  0
  7 10  2  0  0  0  0
  8 10  1  0  0  0  0
  9 12  2  0  0  0  0
 11 12  1  0  0  0  0
M  END
> <PUBCHEM_COMPOUND_ID_TYPE>
0

> <PUBCHEM_TOTAL_CHARGE>
0

> <PUBCHEM_SUBSTANCE_ID>
208675

> <PUBCHEM_SUBSTANCE_VERSION>
3

> <PUBCHEM_EXT_DATASOURCE_NAME>
ChemIDplus

> <PUBCHEM_EXT_DATASOURCE_REGID>
000086840

> <PUBCHEM_SUBSTANCE_SYNONYM>
1-Isocyanatonaphthalene
1-Naphthyl isocyanate
1-Naphthylisocyanate
86-84-0
AI3-15382
EINECS 201-703-7
Isocyanic acid, 1-naphthyl ester (8CI)
NSC 4023
Naphthalene, 1-isocyanato-
alpha-Naphthyl isocyanate

> <PUBCHEM_GENERIC_REGISTRY_NAME>
86-84-0

> <PUBCHEM_XREF_EXT_ID>
000086840

> <PUBCHEM_EXT_DATASOURCE_URL>
http://chem.sis.nlm.nih.gov/chemidplus/

> <PUBCHEM_EXT_SUBSTANCE_URL>
http://chem.sis.nlm.nih.gov/chemidplus/direct.jsp?result=advanced&regno=000086840

> <PUBCHEM_CID_ASSOCIATIONS>
66589  1

$$$$