659283 -OEChem-02060822452D 26 28 0 0 0 0 0 0 0999 V2000 0.0085 -0.4918 0.0000 O 0 0 0 0 0 0 0 0 0 0 0 0 0.8750 -1.9891 0.0000 O 0 0 0 0 0 0 0 0 0 0 0 0 5.2091 0.5048 0.0000 O 0 0 0 0 0 0 0 0 0 0 0 0 4.3389 2.0000 0.0000 O 0 0 0 0 0 0 0 0 0 0 0 0 2.6013 -1.9957 0.0000 N 0 0 0 0 0 0 0 0 0 0 0 0 2.6013 2.0043 0.0000 N 0 0 0 0 0 0 0 0 0 0 0 0 1.7438 -0.4957 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 3.4738 0.5043 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 2.6038 -0.9957 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 2.6038 1.0043 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 3.4738 -0.4957 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 1.7438 0.5043 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 0.8770 -0.9944 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 4.3394 1.0052 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 3.4661 -2.4978 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 1.7340 2.5022 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 4.3339 -2.0009 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 3.4646 -3.5013 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 0.8688 2.0008 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 1.7305 3.5056 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 5.2001 -2.5073 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 4.3258 -3.9991 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 0.0000 2.5030 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 0.8668 3.9991 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 5.1936 -3.5021 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 0.0015 3.4978 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 1 13 2 0 0 0 0 2 13 1 0 0 0 0 3 14 2 0 0 0 0 4 14 1 0 0 0 0 5 9 1 0 0 0 0 5 15 1 0 0 0 0 6 10 1 0 0 0 0 6 16 1 0 0 0 0 7 9 2 0 0 0 0 7 12 1 0 0 0 0 7 13 1 0 0 0 0 8 10 1 0 0 0 0 8 11 2 0 0 0 0 8 14 1 0 0 0 0 9 11 1 0 0 0 0 10 12 2 0 0 0 0 15 17 2 0 0 0 0 15 18 1 0 0 0 0 16 19 2 0 0 0 0 16 20 1 0 0 0 0 17 21 1 0 0 0 0 18 22 2 0 0 0 0 19 23 1 0 0 0 0 20 24 2 0 0 0 0 21 25 2 0 0 0 0 22 25 1 0 0 0 0 23 26 2 0 0 0 0 24 26 1 0 0 0 0 M END > 0 > 0 > 659283 > 3 > ChemIDplus > 010109952 > 1,4-Benzenedicarboxylic acid, 2,5-bis(phenylamino)- 10109-95-2 2,5-Dianilinoterephthalic acid EINECS 233-302-8 > 10109-95-2 > 010109952 > http://chem.sis.nlm.nih.gov/chemidplus/ > http://chem.sis.nlm.nih.gov/chemidplus/direct.jsp?result=advanced®no=010109952 > 82351 1 $$$$