693537 -OEChem-02060822462D 26 25 0 0 0 0 0 0 0999 V2000 12.0151 -1.2534 0.0000 Br 0 0 0 0 0 0 0 0 0 0 0 0 0.7733 1.2534 0.0000 Br 0 0 0 0 0 0 0 0 0 0 0 0 9.4292 0.2500 0.0000 O 0 0 0 0 0 0 0 0 0 0 0 0 3.3592 -0.2500 0.0000 O 0 0 0 0 0 0 0 0 0 0 0 0 12.7884 0.8380 0.0000 O 0 0 0 0 0 0 0 0 0 0 0 0 10.8624 1.9564 0.0000 O 0 0 0 0 0 0 0 0 0 0 0 0 0.0000 -0.8380 0.0000 O 0 0 0 0 0 0 0 0 0 0 0 0 1.9260 -1.9564 0.0000 O 0 0 0 0 0 0 0 0 0 0 0 0 8.5592 -1.2500 0.0000 O 0 0 0 0 0 0 0 0 0 0 0 0 4.2292 1.2500 0.0000 O 0 0 0 0 0 0 0 0 0 0 0 0 11.1592 0.2500 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 1.6292 -0.2500 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 10.2892 -0.2500 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 2.4992 0.2500 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 12.0192 -0.2500 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 0.7692 0.2500 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 11.8040 1.0143 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 10.5182 1.0175 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 0.9843 -1.0143 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 2.2702 -1.0175 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 8.5592 -0.2500 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 4.2292 0.2500 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 7.6892 0.2500 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 5.0992 -0.2500 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 6.8292 -0.2500 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 5.9592 0.2500 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 1 15 1 0 0 0 0 2 16 1 0 0 0 0 3 13 1 0 0 0 0 3 21 1 0 0 0 0 4 14 1 0 0 0 0 4 22 1 0 0 0 0 5 17 1 0 0 0 0 6 18 1 0 0 0 0 7 19 1 0 0 0 0 8 20 1 0 0 0 0 9 21 2 0 0 0 0 10 22 2 0 0 0 0 11 13 1 0 0 0 0 11 15 1 0 0 0 0 11 17 1 0 0 0 0 11 18 1 0 0 0 0 12 14 1 0 0 0 0 12 16 1 0 0 0 0 12 19 1 0 0 0 0 12 20 1 0 0 0 0 21 23 1 0 0 0 0 22 24 1 0 0 0 0 23 25 1 0 0 0 0 24 26 1 0 0 0 0 25 26 1 0 0 0 0 M END > 0 > 0 > 693537 > 3 > ChemIDplus > 070776317 > 70776-31-7 Hexanedioic acid, bis(2,2-di(hydroxymethyl)-3-bromopropyl) ester Hexanedioic acid, bis(3-bromo-2,2-bis(hydroxymethyl)propyl) ester > 70776-31-7 > 070776317 > http://chem.sis.nlm.nih.gov/chemidplus/ > http://chem.sis.nlm.nih.gov/chemidplus/direct.jsp?result=advanced®no=070776317 > 116880 1 $$$$