702381
  -OEChem-02060822462D

 13 13  0     0  0  0  0  0  0999 V2000
    6.5750   -3.0583    0.0000 Br  0  0  0  0  0  0  0  0  0  0  0  0
    1.5792   -4.2917    0.0000 As  0  0  0  0  0  0  0  0  0  0  0  0
    5.1458   -3.8875    0.0000 O   0  0  0  0  0  0  0  0  0  0  0  0
    0.8625   -3.8792    0.0000 O   0  0  0  0  0  0  0  0  0  0  0  0
    4.4375   -2.6500    0.0000 N   0  0  0  0  0  0  0  0  0  0  0  0
    3.7259   -3.0706    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    2.2981   -3.8862    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    3.7246   -3.8904    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    3.0186   -2.6586    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    3.0082   -4.3018    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    2.3029   -3.0650    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    5.1500   -3.0625    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    5.8625   -2.6458    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
  1 13  1  0  0  0  0
  2  4  2  0  0  0  0
  2  7  1  0  0  0  0
  3 12  2  0  0  0  0
  5  6  1  0  0  0  0
  5 12  1  0  0  0  0
  6  8  2  0  0  0  0
  6  9  1  0  0  0  0
  7 10  2  0  0  0  0
  7 11  1  0  0  0  0
  8 10  1  0  0  0  0
  9 11  2  0  0  0  0
 12 13  1  0  0  0  0
M  END
> <PUBCHEM_COMPOUND_ID_TYPE>
0

> <PUBCHEM_TOTAL_CHARGE>
0

> <PUBCHEM_SUBSTANCE_ID>
702381

> <PUBCHEM_SUBSTANCE_VERSION>
3

> <PUBCHEM_EXT_DATASOURCE_NAME>
ChemIDplus

> <PUBCHEM_EXT_DATASOURCE_REGID>
067278313

> <PUBCHEM_SUBSTANCE_SYNONYM>
4-((Bromoacetyl)amino)phenyl arsenoxide
67278-31-3
Acetamide, N-(4-arsenosophenyl)-2-bromo-
BAAPA
p-((Bromoacetyl)amino)phenyl arsenoxide
p-((Bromoacetyl)amino)phenylarsenoxide
para-((Bromoacetyl)amino)phenyl arsenoxide

> <PUBCHEM_GENERIC_REGISTRY_NAME>
67278-31-3

> <PUBCHEM_XREF_EXT_ID>
067278313

> <PUBCHEM_EXT_DATASOURCE_URL>
http://chem.sis.nlm.nih.gov/chemidplus/

> <PUBCHEM_EXT_SUBSTANCE_URL>
http://chem.sis.nlm.nih.gov/chemidplus/direct.jsp?result=advanced&regno=067278313

> <PUBCHEM_CID_ASSOCIATIONS>
125631  1

$$$$