766616
  -OEChem-02060822472D

 13 14  0     1  0  0  0  0  0999 V2000
    4.8324    1.3589    0.0000 O   0  0  0  0  0  0  0  0  0  0  0  0
    6.9975    1.3589    0.0000 O   0  0  0  0  0  0  0  0  0  0  0  0
    6.9975   -1.1411    0.0000 N   0  0  0  0  0  0  0  0  0  0  0  0
    4.8324   -1.1411    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    5.9150   -0.5161    0.0000 C   0  0  3  0  0  0  0  0  0  0  0  0
    4.8324   -2.3911    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    5.9150    0.7339    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    3.7499   -0.5161    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    5.9150   -3.0161    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    3.7499   -3.0161    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    6.9975   -2.3911    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    2.6674   -1.1411    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    2.6674   -2.3911    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
  1  7  2  0  0  0  0
  2  7  1  0  0  0  0
  3  5  1  0  0  0  0
  3 11  1  0  0  0  0
  4  5  1  0  0  0  0
  4  6  2  0  0  0  0
  4  8  1  0  0  0  0
  5  7  1  0  0  0  0
  6  9  1  0  0  0  0
  6 10  1  0  0  0  0
  8 12  2  0  0  0  0
  9 11  1  0  0  0  0
 10 13  2  0  0  0  0
 12 13  1  0  0  0  0
M  END
> <PUBCHEM_COMPOUND_ID_TYPE>
0

> <PUBCHEM_TOTAL_CHARGE>
0

> <PUBCHEM_SUBSTANCE_ID>
766616

> <PUBCHEM_SUBSTANCE_VERSION>
3

> <PUBCHEM_EXT_DATASOURCE_NAME>
ChemIDplus

> <PUBCHEM_EXT_DATASOURCE_REGID>
041034520

> <PUBCHEM_SUBSTANCE_SYNONYM>
1,2,3,4-Tetrahydroisoquinoline carboxylic acid
1-Isoquinolinecarboxylic acid, 1,2,3,4-tetrahydro-
41034-52-0
L-Tetrahydro-3-isoquinoline carboxylic acid
THIQC
Tetrahydroisoquinoline carboxylic acid

> <PUBCHEM_GENERIC_REGISTRY_NAME>
41034-52-0

> <PUBCHEM_XREF_EXT_ID>
041034520

> <PUBCHEM_EXT_DATASOURCE_URL>
http://chem.sis.nlm.nih.gov/chemidplus/

> <PUBCHEM_EXT_SUBSTANCE_URL>
http://chem.sis.nlm.nih.gov/chemidplus/direct.jsp?result=advanced&regno=041034520

> <PUBCHEM_CID_ASSOCIATIONS>
189112  1

$$$$