3869239
  -OEChem-02060822592D

 13 13  0     0  0  0  0  0  0999 V2000
    4.6356   -1.3074    0.0000 S   0  0  0  0  0  0  0  0  0  0  0  0
    6.8591   -2.4249    0.0000 O   0  5  0  0  0  0  0  0  0  0  0  0
    6.8591   -4.5900    0.0000 O   0  0  0  0  0  0  0  0  0  0  0  0
    4.2493   -4.5187    0.0000 N   0  0  0  0  0  0  0  0  0  0  0  0
    3.0605   -2.8825    0.0000 N   0  0  0  0  0  0  0  0  0  0  0  0
    6.2341   -3.5075    0.0000 N   0  3  0  0  0  0  0  0  0  0  0  0
    4.3988    1.9913    0.0000 N   0  0  0  0  0  0  0  0  0  0  0  0
    4.9841   -3.5075    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    4.2493   -2.4962    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    3.0605   -4.1325    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    2.0493   -4.8672    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    3.7517   -0.4235    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    4.0753    0.7839    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
  1  9  1  0  0  0  0
  1 12  1  0  0  0  0
  2  6  1  0  0  0  0
  3  6  2  0  0  0  0
  4  8  1  0  0  0  0
  4 10  1  0  0  0  0
  5  9  1  0  0  0  0
  5 10  2  0  0  0  0
  6  8  1  0  0  0  0
  7 13  3  0  0  0  0
  8  9  2  0  0  0  0
 10 11  1  0  0  0  0
 12 13  1  0  0  0  0
M  CHG  2   2  -1   6   1
M  END
> <PUBCHEM_COMPOUND_ID_TYPE>
0

> <PUBCHEM_TOTAL_CHARGE>
0

> <PUBCHEM_SUBSTANCE_ID>
3869239

> <PUBCHEM_SUBSTANCE_VERSION>
2

> <PUBCHEM_EXT_DATASOURCE_NAME>
ChemIDplus

> <PUBCHEM_EXT_DATASOURCE_REGID>
110579005

> <PUBCHEM_SUBSTANCE_SYNONYM>
((2-Methyl-5-nitro-1H-imidazol-4-yl)thio)acetonitrile
110579-00-5
2-((2-Methyl-4-nitro-1H-imidazol-5-yl)thio)acetonitrile
Acetonitrile, ((2-methyl-5-nitro-1H-imidazol-4-yl)thio)-
BRN 5532982

> <PUBCHEM_GENERIC_REGISTRY_NAME>
110579-00-5

> <PUBCHEM_XREF_EXT_ID>
110579005

> <PUBCHEM_EXT_DATASOURCE_URL>
http://chem.sis.nlm.nih.gov/chemidplus/

> <PUBCHEM_EXT_SUBSTANCE_URL>
http://chem.sis.nlm.nih.gov/chemidplus/direct.jsp?result=advanced&regno=110579005

> <PUBCHEM_CID_ASSOCIATIONS>
3066575  1

$$$$